Molecular Orbital Theory, Valence Bond Theory And Hybridization Worksheets

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Chemistry 121 Problem set VI solutions - 1
Valence Bond Theory and
Chem 121 Problem Set VI
Molecular Orbital Theory,
Hybridization
1.
H
Te
2
a) Te is in Group VI, so Lewis structure is analogous to H
O (first structure)
2
b) VSEPR
2 bp + 2 lp = 4
shape is tetrahedral
c) Molecular shape is bent
3
d) Hybridization is sp
(VSEPR 4 pairs on central atom so need 4 orbitals)
e) Polar. ∆EN (H-Te) ≈ 0. Resultant vector comes from the two lone pair ∆EN vectors (second structure)
H
H
Te
H
H
CBr
4
a) Lewis structure is first structure
b) VSEPR
4 bp + 0 lp = 4
shape is tetrahedral
c) Molecular shape is tetrahedral
3
d) Hybridization is sp
(VSEPR 4 pairs on central atom so need 4 orbitals)
e) Nonpolar. ∆EN (Br-C) = 0.3. All 4 ∆EN (C-Br) vectors cancel. Second structure shows the two opposing
resultants for two ∆EN (C-Br) vectors.
Br
Br
Br
Br
C
Br
Br
Br
Br
AsCl
5
a) Lewis structure is first structure
b) VSEPR
5 bp + 0 lp = 5
shape is trigonal bipyramid
c) Molecular shape is trigonal bipyramid
3
d) Hybridization is sp
d (VSEPR 5 pairs on central atom so need 5 orbitals)
e) Nonpolar. ∆EN (Cl-As) = 0.9. All 5 ∆EN (Cl-As) vectors cancel. Second structure shows the two vertical
vectors will cancel and the three vectors in the triangular plane will cancel.
Cl
Cl
Cl
As
Cl
Cl
AsCl
3
a) Lewis structure is first structure and has an extra lone pair on the central atom
b) VSEPR
3 bp + 1 lp = 4
shape is tetrahedral
c) Molecular shape is trigonal pyramid (second structure).
3
d) Hybridization is sp
(VSEPR 4 pairs on central atom so need 4 orbitals)
e) Weakly polar. ∆EN (Cl-As) = 0.9. The 3 ∆EN (Cl-As) vectors will give a resultant pointing down. The
lone pair gives a vector pointing up and these two vectors will come close to cancelling.
As
Cl
Cl
As
Cl
Cl
Cl
Cl
CO
2
a) Lewis structure is first structure
b) VSEPR
2 bp + 0 lp = 2 (multiple bonds count as one bp)
shape is linear
c) Molecular shape is linear
d) Hybridization is sp (VSEPR 2 pairs on central atom so need 2 orbitals)

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