Physics Phy231 Exam 2 Section 2 Form D With Answers - Michigan State University Department Of Physics And Astronomy - Spring 2013 Page 2
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1
2
3Form D
Exam 2 PHY231 Spring 2013 Section 2
6. A 71.0-kg man stands on a bathroom scale in an
scale reads normal force, N
elevator. What does the scale read if the elevator is
2
ma = F
= N − mg
ascending with an acceleration of 3.00 m/s
?
net
A) 697 N
E) 910 N
N = m(a + g) = (71.0kg)(3.00+9.81)m/s
2
B) 213 N
F) 537 N
= 910 N
C) 484 N
G) 362 N
D) 142 N
H) 440 N
6
7. The kinetic energy of a car is 8.00×10
J as it travels along a horizontal road. How much work
is required to stop the car in 10 s?
7
A) 0.00 J
E) 8.00×10
J
4
8
B) 8.00×10
J
F) 8.00×10
J
W = ΔK = 8.00 × 10
6
J
5
9
C) 8.00×10
J
G) 8.00×10
J
6
10
D) 8.00×10
J
H) 8.00×10
J
8. A 10.0 g bullet traveling horizontally at 755 m/s strikes a stationary target and stops after
penetrating 14.5 cm into the target. What is
the average force of the target on the bullet?
W = F
Δx = ΔK
4
4
x
A) 1.97×10
N
E) 3.93×10
N
5
5
ΔK
2
2
mv
B) 2.07×10
N
F) 5.67×10
N
1
(0.5)(0.010kg)(755m/s)
=
=
=
= 1.97 × 10
4
F
2
N
3
4
C) 6.26×10
N
G) 8.03×10
N
x
Δx
Δx
0.145m
4
4
D) 3.13×10
N
H) 1.12×10
N
9. A projectile is launched with a momentum of 200 kg ï m/s and 1000 J of kinetic energy. What
is the mass of the projectile?
A) 5.00 kg
E) 25 kg
(
)
2
200kg ⋅ m/s
B) 10.0 kg
F) 30 kg
2
2
p
p
= K ⇒ m =
=
= 20kg
C) 15.0 kg
G) 40 kg
2m
2K
2(1000J)
D) 20.0 kg
H) 50 kg
A skier leaves the top of a slope with an initial
10.
K + U = K
+ U
; U = 0
0
0
speed of 5.00 m/s. Her speed at the bottom of the
=
+ mgy
2
2
mv
mv
1
1
slope is 13.0 m/s. What is the height of the slope?
0
2
2
A) 11.0 m
E) 1.82 m
− v
− (5m/s)
2
2
2
2
v
(13m/s)
0
y =
= 0.5
1
B) 9.82 m
F) 5.55 m
2
2
g
9.81m/s
C) 6.56 m
G) 8.02 m
= 7.34m
D) 7.34 m
H) 3.57 m
11. A football player kicks a 0.41-kg football initially at rest; and the ball flies through the air. If
the kicker's foot was in contact with the ball for 0.051 s and the ball's initial speed after the
collision is 21.0 m/s, what was the magnitude of the average force on the football?
A) 9.70 N
E) 135 N
FΔt = Δp
B) 46.0 N
F) 152 N
C) 81.1 N
G) 169 N
Δp
(0.41kg)(21m/s)
F =
=
= 169 N
D) 190 N
H) 243 N
Δt
0.051s
2
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