NCERT/CBSE MATHEMATICS CLASS 12 textbook
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MISCELLANEOUS EXERCISES
Answers to NCERT/CBSE MATH (Class XII)textbook
Chapter 9
DIFFERENTIAL EQUATIONS
2.( )
i
x
−
x
2
y ae
=
+
be
+
x
dy
⇒
x
−
x
=
ae
−
be
+
2
x
dx
2
d y
⇒
x
−
x
=
ae
+
be
+
2
2
dx
⇒ −
x
−
x
2
2
x
−
x
y ae
=
+
be
+
x
y x
=
ae
+
be
2
d y
⇒
x
−
x
2
=
ae
+
be
+ = −
2
y x
+
2
2
dx
2
d y
dy
2
Now x
+
2
−
xy x
+
−
2
2
dx
dx
(
) (
)
2
x
−
x
2
=
x y x
−
+
2
+
2
ae
−
be
+
2
x
−
xy x
+
−
2
3
x
−
x
2
=
xy x
−
+
2
x
+
2
ae
−
2
be
+
4
x xy x
−
+
−
2
3
x
−
x
2
= −
x
+
2
ae
−
2
be
+
6
x x
+
− ≠
2 0
The given expression is not a solution of the given differential equation
Please do not copy the answer given here
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