Chemistry Reference Sheet
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43.4 Calculating Amounts of Reactants
Mole-to-Mole Conversions
and Products
• Conversion method
Stoichiometric Equivalences
– The mole ratios are used as conversion factors
• Balanced chemical equations contain definite
(mol
given)×(mole ratio) =
(mol
required)
stoichiometric relations between reactants and
Example:
products → stoichiometric mole ratios
Determine the number of moles of
water produced from 3.4 mol O
.
Example:
→ 2H
2H
+ O
O
2
2
2
2
→ 2H
→ balanced equation:
2H
+ O
O
⇔ 1 mol O
2 mol H
2
2
2
2
2
stoichiometric
⇔ 2 mol H
→
2 mol H
O
[2 mol H
O/1 mol O
]
mole ratio (conversion factor):
2
2
equivalences
2
2
⇔ 2 mol H
1 mol O
O
2
2
1 mol O
/ 2 mol H
2
mol
H
O
2
2
stoichiometric
×
=
2
3.4
mol
O
6
.
8
mol
H
O
2 mol H
O / 2 mol H
2
2
1
mol
O
mole ratios
2
2
2
2 mol H
O / 1 mol O
2
2
• Stoichiometric conversion factors are reaction
Mass-to-Mass Calculations
specific
• Conversion method
Example:
Calculate the amount of O
needed to
2
produce 3.5 mol H
O by combustion of methane
2
(CH
).
4
→ balanced equation:
→ CO
CH
+ 2O
+ 2H
O
4
2
2
2
→ mole ratio (conversion factor):
⇔ 2 mol H
2 mol O
O
2
2
[2 mol O
/2 mol H
O]
2
2
2
mol
O
×
=
3.5
mol
H
O
2
3
.
5
mol
O
2
2
2
mol
H
O
2
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