Ibps Po Exam Template With Answers Page 27
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32IBPS PO Pre 2016 – Model Paper 4
n(E) = Number of ways of drawing 1 red ball out of 4 and 2 white balls out of 6
= (4C1 × 6C2 )
= 4 × (6 × 5) / (2 × 1) = 60
P (E) = n(E) / n(S) = 60 / 20 = 1 / 2
32) Option 4
Clearly, n(S) = 52C2 = (52 × 51) / 2 = 1326
Let E1 = event of getting both red cards,
E2 = event of getting both kings
Then, E1 ∩ E2 = event of getting 2 kings of red cards.
n (E1) = 26C2 = (26 ×25) / (2 × 1) = 325 ; n (E2) = 4C2 = (4 ×3) / (2 × 1) = 6
n ( E1 ∩ E2) = 2C2 = 1
P (E1 = nE1 / n (S) = 325 / 1326
P (E2) = nE2 / n (S) = 6 / 1326
P (E1 ∩ E2) = 1 / 1326
P (both red or both kings) = P (E1 U E2 )
= P (E1 ) + P (E2 ) = P (E1 ∩ E2)
= 325 / 1326 + 6 / 1326 - 1 / 1326
= 330 / 1326
= 55 / 221
33. (Option 2)
Here, n(S) = 52
There are 13 cards of diamond (including one king) and there are 3 more kings.
Let E = event of getting a diamond or a king.
Then, n(E) = (13 + 3) = 16
P (E) = 16 / 52 = 4 / 13
34)
Option 3
9000 ----- 150%
Page 27
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