Sat Math Easy Practice Worksheet With Answer Key Page 12

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SAT Math Easy Practice Quiz #2 Answers
7. C
(Estimated Difficulty Level: 1)
10. D
(Estimated Difficulty Level: 2)
Which of the points on the graph is at the bottom of the
If you got stuck here, try working with the answers: sub-
parabola? That point will give you the minimum value
stitute each answer into m until the inequality works.
of y. Since figures on the SAT are accurately drawn
If you plug in answer D, you get |2(1)
2| = 0 which is
unless the problem says otherwise, you can see that the
less than 1, so answer D is correct.
point ( 1, 2) is at the bottom of the curve. So, the
How would you do this problem the “real” way? The
needed x-value is
1. One mini-trap to avoid here is:
expression |x| < 5, for example, means that x is less
the problem asked you for the x-value, which is
1, not
than 5 units away from 0 on the number line. In other
the y-value, which is
2. Hopefully you didn’t fall for
words, x is bigger than
5 and less than 5. In math,
answer B, which inconveniently gives the y-value. Once
this is:
5 < x < 5. So, |2m
2| < 1 is the same
again, I have no idea at all how that answer got there!
thing as:
1 < 2m
2 < 1. Adding 2 to all sides gives
1 < 2m < 3 so that 1/2 < m < 3/2, which means that
m must be equal to 1.
8. 4
(Estimated Difficulty Level: 1+)
Hint: square both sides of the equation! When you
do that, the square roots disappear and you get the
11. A
(Estimated Difficulty Level: 2)
equivalent equation: 2m + 1 = 3m
3. Solving for m
gives m = 4.
Mmmm, there’s nothing quite like a cabbage barrel.
Anyway, if the algebra isn’t working for you here, plug
If you were really stuck on how to proceed here, re-
in real numbers for n. When it comes to percents or
member one of your basic SAT math strategies: plug in
probabilities, numbers like 100 are good choices to plug
numbers for variables. Since grid-in answers are always
in, so let’s try n = 100. For the probability of choosing
0 or greater, you could try plugging in 0, 1, and so forth.
a green cabbage to be 30% when there are 100 cab-
When the equation works, the answer must be correct.
bages in the barrel, there must be 30 green cabbages,
since that number makes the probability of picking a
green cabbage 30/100 = 30%. Now, work through the
answers plugging in n = 100 until you get the answer
9. B
(Estimated Difficulty Level: 2)
30. Answer A gives 3(100)/10 = 30 so that must be the
correct answer.
Occasionally, an SAT math problem will have an “E”
answer that states that the problem can’t be solved us-
Algebra mavens and math teachers will do the following:
ing the given information. For these questions, answer
Let x be the number of green cabbages. Then, the
E is correct only about 11% of the time, using the last
probability of choosing a green cabbage is x/n, which
few years of SAT tests. So when you see one of these,
equals 30%, so that
you should think: “Answer E is probably a trap.” And
x
30
3
that is true for this problem as well! We don’t know
=
=
n
100
10
what a and b are, but it doesn’t matter: plug in real
numbers for a and b. We need a + b = c = 12, so I’ll try
and we get x = 3n/10. Those mavens will do this al-
a = 5 and b = 7. Then, c
2a
2b = 12
2(5)
2(7) =
gebra smugly, but you can get the same question right
12
10
14 =
12, making B the correct answer.
just by plugging in numbers.
If you are an algebra fiend, you’ll see that c
2a
2b =
c 2(a + b) = c 2(c) =
c =
12. But you don’t have
to be a fiend to get this question right.
pg. 12

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