Writing Chemical Formula Worksheet With Answer Key - Spes Unica Page 22
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28Example 2: What is the concentration of a solution of hydrochloric
acid containing 0.1 mol in 50 cm 3 ?
Concentration = number of moles
Volume (in litres)
= 0.1 ÷ (50÷1000)
= 2 mol/l
Example 3: What volume of a sodium carbonate solution, concentration 2
mol/l contains 0.5 mol?
Volume (in litres) = number of moles
Concentration
= 0.5÷ 2
=0.25 l (or 250 ml)
Calculations involving both triangles.
Some calculations will require using both triangles.
Example 4: What is the concentration of a solution containing 2 g
sodium hydroxide, NaOH, in 50 cm solution?
Concentration = number of moles
Volume (in litres)
However we do not yet know the number of moles so we must firstly
calculate this using the equation
Number of moles = mass of substance in grams
formula mass
Formula mass of NaOH = (23+16+1)
= 40g
Number of moles = mass of substance in grams
formula mass
= 2 ÷ 40
= 0.05 moles
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