Math 333 Logarithms Worksheet With Answers Page 6
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1
2
3
4
5
6
7
8
9
10
11
12
135
4
3
2
1
0
0.5
1
1.5
2
2.5
3
omega
(d) Find the maximum value of A and the frequency ω for which it occurs.
Solution: Again following B&D p. 203, we have
2
R
=
max
( 2/4) 1
(1/128)
8
=
1
2
64
5.679.
The value of ω that gives this peak is
1
ω
=
2
max
32
63
=
32
= 1.403.
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