Percent Composition And Empirical Formula Worksheet With Answers
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6Percent Composition
Empirical Formula
1)!
Determine the % composition by mass for each of the following;
!
a)!
Percentage of carbon in!
C
H
2
6
!
!
2 x C ! = 2 x 12.0 !
= !
24.0! !
% = ! 24.0! =!
80.0 %
!
6 x H ! = 6 x 1.0!
=!
6.0! !
!
30.0
!
!
!
!
!
30.0 amu
!
b)!
Percentage of iron in!
FeCl
3
!
1 x Fe != 1 x 55.8 !
= !
55.8! !
% = ! 55.8! =!
34.4 %
!
!
3 x Cl != 3 x 35.5!
= !
106.5! !
!
162.3
!
!
!
!
!
162.3 amu
!
c)!
Percentage of oxygen in!
C
H
O
2
4
2
2 x C ! = 2 x 12.0 !
= !
24.0! !
% = ! 32.0! =!
53.3 %
!
!
4 x H ! = 4 x 1.0!
= !
4.0! !
!
60.0
!
2 x O ! = 2 x 16.0!
= !
32.0! !
!
!
!
!
!
!
!
!
60.0 amu
!
d)!
Percentage of carbon in!
CaCO
3
!
1 x Ca ! = 1 x 40.1 !
= !
40.1! !
% = ! 12.0! =!
12.0 %
!
!
1 x C! = 1 x 12.0!
= !
12.0! !
!
100.1
!
3 x O ! = 3 x 16.0!
= !
48.0! !
!
!
!
!
!
!
!
100.1 amu
!
e)!
Percentage of sodium in!
NaOH
!
1 x Na = 1 x 23.0 !
= !
23.0! !
% = ! 23.0! =!
57.5 %
!
1 x H ! = 1 x 1.0!
= !
1.0! !
!
40.0
!
1 x O ! = 1 x 16.0!
= !
16.0! !
!
!
!
!
!
!
!
!
40.0 amu
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