Trigonometric Functions - Unit Circle Approach Worksheet Page 7
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1
2
3
4
5
6
7
8
9
10
11
1218
3
1
π
π
sin(
) = y
=
cos(
) = x
=
uc
uc
6
2
6
2
1
y
3
3
1
1
2
1
π
÷
uc
2
tan(
) =
=
=
=
=
=
•
x
6
2
2
2
3
3
3
3
uc
2
1
1
2 3
1
1
2
π
π
csc(
) =
=
= 2
sec(
) =
=
=
=
y
x
6
1
6
3
3
3
uc
uc
2
2
3
x
3
3
1
2
π
÷
uc
2
cot(
) =
=
=
=
=
3
•
y
1
6
2
2
2
1
uc
2
2
2
)
(
b) The terminal side of θ intersects
,
on the unit circle. So,
2
2
2
2
π
π
sin(
) = y
=
cos(
) = x
=
uc
uc
2
2
4
4
2
y
1
1
2
π
π
uc
2
tan(
) =
=
= 1
csc(
) =
=
=
=
2
x
y
4
4
2
2
2
uc
uc
2
2
2
x
1
2
π
π
uc
2
sec(
) =
=
=
2
cot(
) =
=
= 1
y
4
4
2
2
2
uc
2
2
3
(
)
1
c) The terminal side of θ intersects
,
on the unit circle. Thus,
2
2
3
1
π
π
sin(
) = y
=
cos(
) = x
=
uc
uc
3
2
3
2
3
y
3
3
1
2
π
÷
uc
2
tan(
) =
=
=
=
=
3
•
x
3
1
2
2
2
1
uc
2
1
2 3
1
1
2
1
π
π
csc(
) =
=
=
=
sec(
) =
=
= 2
y
x
1
3
3
3
3
3
uc
uc
2
2
1
x
3
3
1
1
2
1
π
÷
uc
2
cot(
) =
=
=
=
=
=
•
y
3
2
2
2
3
3
3
3
uc
2
We can summarize our results:
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