Solving Word Problems With Equations Of One Degree And One Unknown Worksheet With Answers Page 8
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20For this particular problem the chart would look like this:
!
Rate
Time
Distance
Bike
15
Car
35
The rates are specifically given, so they are filled in immediately. The rate, time,
!
or distance put in the chart must for be that particular vehicle only (NO totals or
averages of them).
Now, a diagram helps you get your bearings. Use arrows to represent
!
the situation
10 MILES
BIKE
CAR
The arrows go the same way to represent “the same direction.” The ‘start’ of the
!
arrows is not the same; the bike is 10 miles out in front (from the given
information). Note how we mark that on the diagram. The ‘stop’ of the arrows is
the same because we’re talking about when they meet.
Reread the problem. It asks us to find how many hours each has traveled, i.e.
!
time. The start and stop times in the problem are the same. It is the distances that
aren’t the same. Each vehicle travels the same amount of time. We can represent
that time by X.
We put that information on the chart:
!
Rate
Time
Distance
X
Bike
15
15X + 10
Car
35
X
35X
!
The third column (in this case, distance) is filled in using the formula, D = R * T. This formula can
be solve in terms of R or T and these forms are used when your third column to be filled in is time
or rate.
d
t
=
r
!
d
r
=
t
For this problem, we multiply across the rows of the chart to use the formula:
!
Once the chart is completed we direct our attention to the equation.
!
From the reading we can see the distance traveled by the car is 10 more
!
miles than the distance traveled by the bike. So we can write the
equation:
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