Chemical Calculations And Chemical Formulas Worksheets With Answer Key Page 10
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Study Guide for An Introduction to Chemistry
Section 9.3 Molar Mass and Chemical Compounds
33. For each of the following molecular substances, calculate its molecular mass and write a
conversion factor that converts between mass in grams and moles of the substance.
(Objs 5 & 6)
a. H
PO
3
2
molecular mass H
PO
= 3(1.00794) + 1(30.9738) + 2(15.9994)
3
2
65.9964 g H PO
3
2
= 65.9964 leads to
1 mol H PO
3
2
b. C
H
NH
6
5
2
molecular mass C
H
NH
= 6(12.011) + 7(1.00794) + 1(14.0067)
6
5
2
93.128 g C H NH
6
5
2
= 93.128 leads to
1 mol C H NH
6
5
2
35. Each dose of nighttime cold medicine contains 1000 mg of the analgesic acetaminophen.
NO. (Obj 7)
Acetaminophen, or N-acetyl-p-aminophenol, has the general formula C
H
8
9
a. How many moles of acetaminophen are in each dose?
1 g
1 mol C H NO
8
9
? mol C H NO = 1000 mg C H NO
8
9
8
9
3
10 mg
135.166 g C H NO
8
9
= 7.398 10
–3
mol C
H
NO
8
9
b. What is the mass in grams of 15.0 moles of acetaminophen?
135.166 g C H NO
= 2.03 10
3
8
9
? g C H NO = 15.0 mol C H NO
g C
H
NO
8
9
8
9
8
9
1 mol C H NO
8
9
38. For each of the following examples, decide whether it would be better to use the term
(Obj 9)
molecule or formula unit .
a. Cl
O
molecular compound - molecules
2
b. Na
O
ionic compound – formula units
2
c. (NH
)
SO
ionic compound – formula units
4
2
4
d. HC
H
O
molecular compound - molecules
2
3
2
40. For each of the following ionic substances, calculate its formula mass and write a conversion
factor that converts between mass in grams and moles of the substance. (Objs 10 & 11)
a. BiBr
3
formula mass BiBr
= 1(208.9804) + 3(79.904)
3
448.69 g BiBr
3
= 448.69 leads to
1 mol BiBr
3
b. Al
(SO
)
2
4
3
formula mass Al
(SO
)
= 2(26.9815) + 3(32.066) + 12(15.9994)
2
4
3
342.154 g Al (SO )
2
4 3
= 342.154 leads to
1 mol Al (SO )
2
4 3
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