Systems Of Equations Math Worksheet Page 2

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2x + 3 = x + 2
Since “y” is equal to both 2x + 3 and x + 2, then they are
equal to each other! Then, we can solve for “x” and plug our
value back into either equation to get “y”. It doesn’t matter
which, as we should get the same “y” value either way.
y = (_____) + 2 =
So, my point, is (____, ____).
+
=
2
5
Let’s try this same idea on example 2. We can solve for
x
y
Ex 2:
“y” in either equation above, since the coefficient of “y” is
+
=
2
7
x
y
“1” in both of them, so I’ll use the first: 2x + y = 5
2x + y = 5
y = ________ Å
Now that we’ve found what “y” is equal to, let’s plug it in the
second equation, 2x + y = 7.
2x + (________) = 7 Again, distribute as necessary and
solve for “x”, if possible. In this case, however, see how the
“x”s cancel out? Here we ended up with a statement that is
false. Therefore, there are no places where the lines cross.
Sometimes, we get a true statement instead of a false
statement. In this case, the lines cross everywhere, or are
the same line. This would be the case with example 3.
Using substitution on example 3 is not fun. Here is why.
=
2
3
8
x
y
If we solve either of the equations for either “x” or “y”, then
=
4
6
16
x
y
we end up with fractions. Blar! -
2
8
3
= x
=
+
2x – 3y = 8 is either
or
(and so is 4x – 6y = 16, actually).
4
y
x
y
3
3
2
Either way, plugging in fractions is not necessarily a good time. Luckily, there is
yet another way to do these that works every time and mostly eliminates having to
work with fractions.

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