5 pts
4)
What is E
for the following reaction at 25°C?
cell
2+
-
I
(s)+ Fe(s)Fe
(aq, 0.20M) + 2I
(aq, 0.30 M)
2
RT
E
E
ln
Q
nF
Fe Fe
2+
-
+ 2e
E° =0.44 V
-
2I
-
I
+ 2e
E° = 0.54 V
2
Fe
2+
-
Fe + I
+ 2I
E°=0.98 V
2
2
2
Q
Fe
I
J
. 8
3145
298
K
2
molK
E
. 0
98
V
ln
. 0
20
M
. 0
30
M
. 1
03
V
C
2
mol
96
,
485
mol
5 pts
5)
Write the balanced equation and determine the cell potential for
3+
2+
2+
Pt(s)|Cr
(aq),Cr
(aq)||Cu
(aq)|Cu(s)
Assume standard conditions.
Make sure to include the states in the balanced equation.
2+
Cr
3+
-
Anode
2(Cr
+ e
)
E°= 0.50 V
2+
-
Cu
Cathode
Cu
+2e
E°= 0.34 V
2+
2+
(aq) 2Cr
3+
2Cr
(aq)+Cu
(aq)+Cu(s) E°=0.84
V
5 pts
6)
What is K for the following reaction at 25°C?
4+
(aq) + 2Ag(s) Sn
2+
+
Sn
(aq) + 2Ag
(aq)
E°=0.65 V
Are there more reactants or products at equilibrium?
4+
-
2+
Sn
Sn
+ 2e
+
-
2(AgAg
+ e
)
RT
E
ln
K
nF
. 8
3145
J
298
K
molK
. 0
65
V
ln
K
C
2
96
,
485
mol
ln
K
51
21
K
9
7 .
10
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