Determining the refractive index of water.
1.00
0.80
0.60
0.40
y = 1.3322x - 0.0006
0.20
0.00
0.00
0.10
0.20
0.30
0.40
0.50
0.60
0.70
0.80
sin
1
Determining the refractive index of glycerin.
1.00
0.80
0.60
y = 1.4684x - 0.0022
0.40
0.20
0.00
0.00
0.10
0.20
0.30
0.40
0.50
0.60
0.70
sin
1
Analysis Questions
1. What is the first and second medium?
The first medium is the liquid (water/glycerin) and the second medium is air.
2. What line shape does sin
vs. sin
create? Describe the line or the curve that you produce.
2
1
The shape is a diagonal line (linear). As the sin
is increasing, sin
is also increasing.
1
2
3. What is the average refractive index of your liquid?
It depends on the sample; for water, n=1.33, and for glycerin, n=1.47.
4. At what angle did you start to observe total internal reflection?
It depends on the sample; for water=50º and for glycerin=45º
5. What is the identity of your unknown liquid? Explain your answer.
Either water or glycerin. Explanations will vary, depending on students’ results and
calculations.
Make That Invisible! Activity—Lab Worksheet
Example Answers
2