English, Physics, Mathematics Worksheet With Answers Page 10
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9
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11sin
x
sin
x
−
e
1
−
e
1
samaana hO /
Q15
is equal to_______.
saImaa
Lim
π
sin
x
π
sin
x
→
x
x
→
2
2
(A) e – 1
(B) e + 1
(C) e
(D) e + 2
Ans : A
Q16 λ inayataM k ka maana &at kro M taik naIcao idyaa gayaa flana, x = - 1 pr saM t t hao .
Find the value of the constant λ so that the function given below is continuous
at
2
−
−
x = -1:
f(x) =
x
2
x
3
≠
−
,
x
1
+
x
1
λ
=
−
,
x
1
(A) – 4
(B) 4
(C) 3
(D) –3
Ans : A
cos x
Q17
d
(e
) =______
dx
cos x
cos x
(A) sin x e
(B) – sin x e
cos x
(D) [namao sao kao [ - nahI/None of these
(C) cos x e
Ans : B
-1
Q18
(tan
logx) = __________
d
dx
−
1
1
(A)
(B)
2
2
+
+
x
1 [
(logx)
]
x
1 [
(logx)
]
1
(D) [namao sao kao [ - nahI/None of these
(C)
2
−
1 [
(logx)
]
x
Ans : A
Q19 ek gau b baaro kI i~jyaa 10 sao maI p` i t sao k ND kI dr sao baZ, rhI hO . jaba i~` j yaa 15 sao maI hO tao gau b baaro ka pR Y XIya
xao t ` f la iksa dr sao baZ, rha hO ?
The radius of a ballon is increasing at the rate of 10 cm/sec. At what rate is the
surface area of the ballon increasing when the radius is 15 cm?
2
(A) 1200 π vaga- sao m aI p/ i t sao / 1200 π cm
/sec
2
(B) 120 π vaga- sao m aI p/ i t sao / 120 πcm
/sec
2
(C) 150 π vaga- sao m aI p/ i t sao / 150 π cm
/sec
2
(D) 1500 π vaga- sao m aI p/ i t sao / 1500 π cm
/sec
Ans : A
3
2
Q20 vah Antrala &at kro M ijasamao M f(x) = 2x
– 36x + 7 yaqaatqya GaT rha hO .
– 3x
3
2
The interval in which the function f(x) = 2x
– 3x
– 36x + 7 is strictly
decreasing is :
(A) (-2, 3)
(B) (-
, -2)
∞
(D) [namao sao kao [ - nahI/None of these
(C) (3,
)
∞
Ans : A
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