Mole Concept Limiting Reactant Worksheet With Answers Page 5
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1
2
3
4
5
6If all 1.25 moles of oxygen are used up
0.2083 mols
Glucose req'd
If all 0.1333 moles of glucose is used up
0.8 mols
Oxygen req'd
For glucose, there're more glucose req'd than what's available so this reactant will run out first.
0.208 > 0.1388
For oxygen, there're more moles available than what's required so there's excess reactant.
1.25 > 0.8328
Answer:
Limiting reactant is glucose
Excess reactant is oxygen
Determine the amount of carbon dioxide produced
H
O
O
CO
O
C
H
6
12
6
2
2
2
+
+
From the balanced equation, we have the ratio of moles of each molecules
1 :
6 :
6 :
6
0.1333333333
Actual moles
X
Using the limiting reactant (the reactant that runs out first) to determine the amount of carbon
dioxide or hydrogen produced.
0.1333 / 1
=
X / 6
X
=
0.8
Mole Concept - Limiting Reactant
Page 5/6
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