Lic Aao Exam Template With Answers Page 25
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25LIC AAO Model Paper 2
III. Z # K ⇒ Z < K : Not true
3
3
3
107. Sol: The series is (× 1 + 1
), (× 2 + 2
), (× 3 + 3
)
F @ H ⇒ F > H
and so on.
69. Statements :
M % H ⇒ M ≤ H
108. Sol: The pattern is (÷ 2 +2), (÷ 2 + 2), and so on.
M $ R ⇒ M ≥ R
118. Sol: Total age of sum boys = 26 × 7
G * M ⇒ G = M
Total age of first three boys = 19 × 3
Total age of last three boys = 32 × 3
Now the age of boy sitting in middle x them
Therefore,
19 × 3 + x + 32 × 3 = 26 × 7
G > H ≥ M = G ≥ R
I. F $ R ⇒ F ≥ R : Not true
x = 182 – 153
Conclusions :
II. F @ R ⇒ F > R : True
x = 29 years
III. H $ G ⇒ H ≥ G : True
119. Sol: Let three consecutive even no are x, x + 2, x +
4
(1)
P # M ⇒ P < M
and three consecutive odd no. are = x –9, x – 7, x –
70. Statements :
M % R ⇒ M ≤ R
5
(2)
R * T ⇒ R = T
By adding (1) + (2)
T # L ⇒ T < L
6x – 15 = 165
6x = 180
x = 30 them x – 9 = 21
Therefore, P < M ≤ R = T < L
I. P # R ⇒ P < R : True
so even no 30, 32, 34 and odd no. = 21, 23, 25
Conclusions :
II. P * R ⇒ P = R : Not true
= sum of the largest even and largest odd no. = 34 + 25
III. M % L ⇒ M ≤ L : Not true
= 59
77. Sol: Meaningful words ⇒ MANE, MEAN, NAME
78. Sol: The sex of F is not given. Therefore, F is either
brother or sister of B.
80. Sol: 10th or 11th July
His friend → 11th, 12th or 13th July
11th July is the common date.
82-86: Sol (82-86):
T
R
M
Q
U
P
V
W
104. Sol: The series is (× 0.5 – 0.5), (× 1 + 1), (× 1.5 –
1.5), (× 2 + 2), (× 2.5 – 2.5)
Page 25
106. Sol: The series is (× 1 + 2), (× 2 + 3) and so on.
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