Model Paper - Rrb (Non-Technical Posts Asm/goods Guards) Worksheet With Answers Page 13
ADVERTISEMENT
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16Model Paper – RRB (Non-technical posts ASM/Goods Guards)
Let the school ages of Neelam and Shaan be
7 (4x + 4) = 9 (3x + 4)
5x and 6x years respectively. Then,
×
x = 8
×
=
[
× 9 × 5x]
So, their present ages are 32 years and 24
years respectively.
= [
× 6x]
15 = 15
Suppose they were married z years ago.
⎯
Thus, Shaan’s age cannot be determined.
⎯
Then,
=
3 (32 - z) = 5 (24 - z)
2z = 24
38. Option C
z = 12
A : B = 60 : 45 and A : C = 60 : 40
35. Option C
So,
= [
×
] = [
×
] =
=
Since Pooja and Shipra are twins so their
= 90 : 80
ages be same. Let their ages be x and age of Monika
be y, then,
x + x = y
… (i)
⎯
So, B can give C 10 points in a game
⎯
of 90.
and
=
7x – 2y = 15
39. Option A
Now, from equation (i),
7x - 4x = 15
When B runs 25 m, A runs
m
x = 5
When B runs 1000 m, A runs [
×
So, the age of Shipra 3 years hence will be 5
+ 3 = 8 years
× 1000] m = 900 m
So, B beats A by 100 m
36. Option B
40. Option B
Let the present ages of Arun and Deepak be
x years and 3x years respectively. Then,
4x +
While A covers 1000 m, B covers (1000 - 40)
6 = 26
m = 960 m and C covers (1000 - 64) m or 936 m
4x = 20
When B covers 960 m, C covers 936
m
x = 5
So, Deepak’s age = 3x = 15 years
When B covers 1000 m, C covers
[
× 1000] m = 975 m
37. Option D
Page 13
ADVERTISEMENT
0 votes
Related Articles
Related forms
Related Categories
Parent category: Education