Model Paper - Rrb (Non-Technical Posts Asm/goods Guards) Worksheet With Answers Page 14
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16Model Paper – RRB (Non-technical posts ASM/Goods Guards)
So, B can give C a start of (1000 - 975) or 25
m
Time taken by pipes A and B to fill the whole
.
tank =
= 6 hours
41. Option A
Capacity filled in 2 hours by pipes A,
B and C = 2 × 13.33 = 26.66%
Remaining capacity = 73.33%
Ratio of the speeds of A and B =
: 1 = 5 : 3
= 4
.
This remaining capacity can be filled by A and
.
Thus, in a race of 5 m, A gains 2 m
B =
over B.
4
So, the total time required
= 2 +
2 m are gained by A in a race of 5 m.
= 6 hours 24 minutes
80 m will be gained A in a race of [
Thus, in this case 24 minutes extra are
× 80] m = 200 m
required.
So, winning post is 200 m away from the
starting point.
45. Option C
1 minute’s work of both the punctures = [
+
42. Option D
] =
= 3
So, both the punctures will make the
A : B = 100 : 90 and A : C = 100 : 87
tyre flat in
min.
=
×
=
×
=
When B runs 30 m, C runs 29 m
46. Option A
47. Option B
When B runs 180 m, C runs [
×
48. Option B
180] m = 174 m
49. Option B
50. Option C
So, B beats C by (180 - 174) m = 6 m
51. Option B
52. Option B
53. Option C
54. Option C
55. Option D
56. Option B
43. Option E
57. Option B
58. Option B
59. Option C
(45 × 16) men can complete the work in 1
60. Option C
day.
61. Option C
62. Option D
So, 1 man’s 1day’s work
=
63. Option C
64. Option D
65. Option A
45 men’s 6 day’s work
= [
66. Option D
× 6] =
67. Option B
68. Option C
69. Option C
Remaining work = [1 -
] =
70. Option D
71. Option D
Page 14
44. Option C
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