Composite Numbers, Prime Numbers, And 1 Worksheet Page 3

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Primes of the form
We can split the odd primes into two distinct groups: those of the form 4k + 1 (the first few being
5, 13, 17, 29, 37, . . .), and those of the form 4k + 3 (the first few being 3, 7, 11, 19, 23, . . .). Since we
know there are infinitely many primes (and only one even prime!), at least one of these two groups
must be infinite. Using an argument similar to Euclid’s proof for all primes, we can show that there
are infinitely many primes of the form 4k + 3. (In fact there are also infinitely many of the form
4k + 1, but this is more difficult to show.)
1. Show that if you multiply together any two numbers of the form 4k + 1 (for instance, 4m + 1
and 4n + 1), you get another number of that form.
2. Explain why any number of the form 4k + 3 has a prime factor of the same form.
3. Now we want to show that there are infinitely many primes of the form 4k+3. Like in Euclid’s
proof, we will start by assuming the
: namely, that there are only finitely many primes
of this form–and from this try to reach some impossible conclusion, a contradiction.
So assume there are only finitely many primes of the form 4k + 3—call them p
, p
, . . . , p .
1
2
Then consider the number N = 4p
p
p + 3. What can you say about this number? In
1
2
particular, which if any of the p ’s is it divisible by?
4. Actually, the number N as defined above
divisible by one of the p ’s. Change the definition
of N slightly so it’s still of the form 4k + 3, but is no longer divisible by any of the primes p
of this form. Why is this a contradiction?
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