Electrons, Bonds And Molecular Properties Worksheet With Answer Key Page 10
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CHAPTER 1
1.35.
a)
H
H
H
H
H
H
C
C
H
C
H
H
C
C C
H
C C
H
H
H
H
H
H
H
H
H
H
H
H
C
H
H
H
C C C
H
C C
H
H
C
C C C
H
H
C
H
C
H
H
H
b)
H
H
H H
H
H
1.36.
H
δ δ δ δ -
δ δ δ δ +
δ δ δ δ +
δ δ δ δ -
H
C
O
H
δ δ δ δ +
δ δ δ δ -
δ δ δ δ +
δ δ δ δ -
δ δ δ δ +
O
δ δ δ δ +
a)
H
Br
b)
H
Cl
c)
H
H
d)
H
1.37.
a) NaBr, because the difference in electronegativity between Na and Br is greater
than the difference in electronegativity between H and Br.
b) FCl, because the disparity in electronegativity between F and Cl is greater than
the disparity in electronegativity Br and Cl.
1.38.
H H
H
C C
O H
H
C C
H
N
a)
b)
H H
H
1.39.
H
H
H
All carbon atoms in this molecule are tetrahedral
H C
C
C C
H
except for the carbon atom bearing the negative
charge, which is trigonal pyramidal.
a)
H
H
H
H
The highlighted carbon atom is tetrahedral, and the
H
other two carbon atoms are trigonal planar.
H O
C
C C
H
The oxygen atom is trigonal pyramidal.
b)
H
H
H
H
H
H
H
Both carbon atoms and the nitrogen atom are tetrahedral.
H N
C
C
O H
The oxygen atom is bent.
c)
H
H
H
H
H
H
All three carbon atoms in this molecule are tetrahedral.
H C
C
C
O
The geometry of the oxygen atom is not relevant
because it is only attached to one other group.
H
H
H
d)
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