Genetics Worksheet With Answer Key - Douglas J. Burks, Wilmington College Of Ohio Page 7

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b is likely dominant since it does not skip generations. Every
individual showing the phenotype has at least one parent with the
trait.
C is likely recessive since it skips two generations.
Problem #31. A young couple went to see a genetic counselor because each had a sibling
affected with cystic fibrosis. (Cystic fibrosis is a recessive disease, and neither member of the
couple nor any of their four parents is affected.)
a. What is the probability that the female of this couple is a carrier?
If the female has a sibling with CF then her parents must
both be heterozygous CFcf x CFcf = .3 + .3 = 2/3 1:CFCF:
2:CFcf: 1 cfcf
b. What are the chances that their child will be affected with cystic fibrosis?
This is complicated.
odds of both being heterozygous is 4/9 (CFcf X CFcf)
If both parents are heterozygous then 25% chance of
offspring being affected. 4/9 x 25 is about 12%
c. What is the probability that their child will be a carrier of the cystic fibrosis mutation?
CFcf x CFcf
.5 x .44 = .22
2 CFcF x
.25 x .44 = .11 and two possibilities = .22
Total odd = .44 or 44%
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