Chemical Bonding Worksheet With Answers Page 6
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1
2
3
4
5
6
7
8
9
10
11
12A
-9
= (0.35 nm)
10B
Furthermore, from the above equation the A is equal to
-9
A = 10B(0.35 nm)
When the above t wo expressions for A/10B and A are substituted into the above expression for E
(- 6.13 eV), t he
0
following results
A
B
− 6.13 eV = = −
+
− 1/ 9
− 10 / 9
⎛
⎞
⎛
⎞
A
A
⎜
⎟
⎜
⎟
⎝
10B
⎠
⎝
10B
⎠
-9
10B(0.35 nm)
B
= −
+
−1/ 9
−10 / 9
[
]
[
]
-9
-9
(0.35 nm)
(0.35 nm)
-9
10B(0.35 nm)
B
= −
+
10
0.35 nm
(0.35 nm)
Or
10B
9B
B
−6.13 eV = = −
+
= −
10
10
10
(0.35 nm)
(0.35 nm)
(0.35 nm)
Solving for B from this equation yields
-5
10
B = 1.88 × 10
eV - nm
Furthermore, the value of A is determined from one of the previous equations, as follows:
(
)
-9
-5
10
-9
A = 10B(0.35 nm)
=
(10)
1.88 × 10
eV - nm
(0.35 nm)
=
2.39 eV - nm
Thus, Equations 2.8 and 2.9 become
.
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