College Level Math Practice Test With Answer Key - Mission Del Paso Campus Page 17
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17Answer Key
30.
C.
Step 1
Step 2
Find the perimeter of the rectangle
Find the circumference of the circle
P = 2L +
2W
C =
·d
↓
↓
↓
↓
↓ ↓
P = 2(200) + 2(50)
C = 3.14(50)
P = 400 + 100
C = 157
P = 400
(400 x 8 laps) + (157 x 8 laps)
Step 3
3200
+
1256 = 4456
Note: When finding the perimeter of composite figures you must delete the side they share from one of the equations,
it you don’t you’ll end up counting that side twice, and your answer will be wrong. That’s why, 100 was deleted from
the perimeter of the rectangle. The rectangle and the circle share that side, so it was deleted from one of the formulas.
31.
D
32.
C
33.
D
34.
C
35.
C
36.
C
37 .
Step 1 This is an unusual problem to solve because you are dealing with the concept of
B
3-dimensions, which usually isn’t covered in great detail until you reach calculus II or III.
Since, we are trying to squeeze the object into the box, we are trying to find the longest
diagonal line within the box.
2
2
2
+ y + z
So, to solve this problem you need to use the following formula:
D
x
2
2
2
You can also write your formula this way D =
l
w
h
2
2
2
+ y + z
D
x
2
2
2
(2)
( )
3
( . )
15
D =
D 4 + 9 + 2.25
D 15.25
D = 3.9 feet
38.
A .
Step 1
You have to find 18% of 35%, so make 35% your base.
18% of 35 is what?
18
a
100
35
a = 6.3
A
opposite
hypotenuse
AC
opposite
39.
SINE =
The answer is SINE =
D.
hypotenuse
AB
C
B
Adjacent
40 .
{do not pick choice “C” the inequality sign is incorrect}
B.
Problems taken from Math 0305 Textbook Intermediate Algebra by K. Elayn Martin-Gay1993, & , and THEA Test
Page 17 of 17
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