INVERSE TRIGONOMETRIC FUNCTIONS
29
(B) is the correct answer.
Solution
One branch of cos
other than the principal value branch corresponds to
–1
Example 23
π
π
π
⎡
⎤
⎧
⎫
3
3
[
]
π
π − ⎨
,
, 2
⎬
(A)
(B)
⎢
⎥
⎣
2 2
⎦
⎩
2
⎭
(C) (0, π)
(D) [2π, 3π]
(D) is the correct answer.
Solution
⎛
π
⎞
⎛
⎞
43
–1
sin
cos
⎜
⎜
⎟
⎟
The value of
is
Example 24
⎝
5
⎠
⎝
⎠
π
− π
π
π
3
7
(A)
(B)
(C)
(D) –
5
5
10
10
π + π
π
⎛
40
3
⎞
⎛
3
⎞
–1
=
–1
π +
sin
cos
sin cos 8
(D) is the correct answer.
⎜
⎟
⎜
⎟
Solution
⎝
5
⎠
⎝
5
⎠
π
⎛
π
π
⎞
⎛
⎞
⎛
⎞
3
3
–1
=
–1
−
sin
cos
sin
sin
⎜
⎟
⎜
⎜
⎟
⎟
=
⎝
5
⎠
⎝
2
5
⎠
⎝
⎠
⎛
π
⎞
π
⎛
⎞
–1
−
= −
sin
sin
⎜
⎜
⎟
⎟
=
.
⎝
10
⎠
10
⎝
⎠
The principal value of the expression cos
[cos (– 680°)] is
–1
Example 25
π
− π
π
π
2
2
34
(A)
(B)
(C)
(D)
9
9
9
9
(A) is the correct answer. cos
(cos (680°)) = cos
[cos (720° – 40°)]
–1
–1
Solution
π
2
= cos
–1
[cos (– 40°)] = cos
–1
[cos (40°)] = 40° =
.
9
The value of cot (sin
–1
x) is
Example 26
x
2
+
1 x
(A)
(B)
+
2
1
x
x