Inverse Trigonometric Functions Worksheets With Answers Page 6

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INVERSE TRIGONOMETRIC FUNCTIONS
23
2
2
1 – cos θ
1 –
x
=
tan θ
=
.
Therefore,
tan(cos
x) =
–1
cosθ
x
2
8
1 –
17
8
15
Hence
.
=
–1
tan cos
=
8
17
8
17
–5
–1
sin 2cot
Find the value of
Example 11
12
–5
5
Let cot
= y . Then cot y =
.
–1
Solution
12
12
–5
–1
sin 2cot
Now
= sin 2y
12
12
–5
π
<
∈ ⎜
2
since cot
0, so
, π
y
y
= 2siny cosy
=
13
13
2
–120
169
1
4
–1
–1
cos sin
sec
Evaluate
Example 12
4
3
1
4
1
3
–1
–1
–1
–1
+
cos sin
sec
cos sin
cos
=
Solution
4
3
4
4
1
3
1
3
–1
–1
–1
–1
cos sin
cos cos
– sin sin
sin cos
=
4
4
4
4
2
2
3
1
1
3
1 –
1 –
=
4
4
4
4
3 15
1 7
3 15 – 7
=
.
4 4
4 4
16

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