Unit 2c Projectile Motion Physics Worksheet Page 6
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29Before we can calculate anything else, we first need to break the original velocity
into components.
We do this so we have a vertical component to do the first couple calculations
with. The horizontal component will be used later.
For now, think vertically!!!
20m/s
sin = opp/hyp
v
y
opp = sin (hyp)
40
= sin 40 (20m/s)
v
opp = v
= 13m/s
x
y
2
2
a) v
= v
+ 2ad
f
i
2
2
2
2
v
v
0
(
13m/s)
f
i
d
= 8.6 m
2
2a
2(-9.81m/s
)
v
v
f
i
a
b)
t
v
v
0
13
m
s /
= 1.3s
f
i
t
But this is only the time to the halfway point
2
a
. 9
81
m
s /
Final answer t = 2.7s
c) It is moving at a constant velocity horizontally the whole time I just
figured out, so let’s use the diagram that was drawn above to get the
horizontal component of the velocity.
cos = adj/hyp
adj = cos (hyp)
= cos40 (20m/s)
adj = v
= 15m/s
x
v = d/t
d = vt
= 15m/s (2.7s)
d = 41 m This is the horizontal distance (range) that it has
traveled.
d) The ball’s velocity when it hits the ground is exactly the same as when it
was originally launched… 20 m/s at 40 up from the horizontal.
6
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