# Lab Session 4, Experiment 3 - Preparation Of Sodium Chloride Worksheet

Lab Session 4, Experiment 3: Preparation of Sodium
Chloride
Sodium chloride will be synthesized by reacting sodium bicarbonate with hydrochloric acid. The
reaction equation is shown below:
+
+
+
NaHCO
HCl
NaCl
H
O
CO
3
(aq)
(aq)
2
(aq)
2
(sol)
(gas)
84.01 g
36.46 g
58.44 g
18.02 g
44.01 g
The quantitative interpretation of the reaction is as follows: 84.01 g (1 mol) of sodium
bicarbonate reacts with 36.46 g (1 mol) of hydrochloric acid to generate 58.44 g (1 mol) of salt,
18.02 g (1 mol) of water, and 44.01 g (or 1 mol) of carbon dioxide. Of course the starting
quantity of NaHCO
may be more or less than 84.01 g, but a proportionate quantity of the
3
hydrochloric acid will be consumed, and proportionate quantities of the products will be formed.
For example, should 100.00 g of NaHCO
react with excess acid, the theoretical mass of salt
3
produced would be calculated as follows:
58.44 g sodium chloride
100.00 g sodium bicarbonate
69.55 g sodium
=
chloride
84.01 g sodium bicarbonate
Note that when a bicarbonate is reacted with excess acid, the salt produced is the only substance
not readily volatile. That is, the unreacted acid, the water, and the carbon dioxide are easily
removed by heating.
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