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Chem 338 Homework #6
6.16) At 300 K, the vapor pressure of dilute solutions of HCl in liquid GeCl4 as as
follows:
x(HCl)
0.005
0.012
0.019
p/kPa
32.0
76.9
121.8
Show that the solution obeys Henry’s law in this range of mole fractions and
calculate the Henry’s law constant at 300 K.
Henry’s law is p
= x
K
, where B = HCl in this case. If this solution obeys
B
B
B
Henry’s law in this mole fraction range, a plot of mole fraction versus vapor
pressure should yield a straight line with a slope given by the Henry’s law constant.
A more accurate method is to fit the data to a quadratic polynomial in x and
evaluate the first derivative at x=0 (this yields the tangent to the curve). Both
methods are shown in the plot below and yield essentially the same result. From the
st
linear fit, one obtains K=6411 kPa or 6.4 MPa, while the 1
derivative of the
quadratic yields 6402 kPa or also 6.4 MPa. Certainly Henry’s law is obeyed for
these concentration ranges.
y = -0.025485 + 6411.2x R= 1
140
8
9
Y = M0 + M1*x + ... M8*x
+ M9*x
120
M 0
-0.0067728
M 1
6402.2
M 2
471.08
100
R
1
80
60
40
20
0
0
0.005
0.01
0.015
0.02

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