Molecular Structure Information Sheet (Page 3 of 3) in pdf

Molecular Structure Information Sheet Page 3

Chemistry 111, section 2, Spring 2006

Answers to even # questions

Chapter 10

D: 120° because the central C has trigonal planar electronic geometry.

b) 1: sp

because the central C has trigonal planar electronic geometry.

2: sp

because the central C has trigonal planar electronic geometry.

3: sp

because the central C has tetrahedral electronic geometry.

10.38.

has 32 electrons. Putting I in the center (it is less electronegative than O) and

making the four sigma bonds leaves 24 electrons. Put 6 LP electrons around each O. That takes

care of all of them, and all atoms have octets, so that is the correct Lewis structure. There are

four sets of sigma BP electrons around the iodine, so the electron geometry is tetrahedral. So is

the molecular geometry since three are no LP electrons on the iodine. The hybridization of I is

as four molecular orbitals are used.

has 40 electrons. I must be in the center. Put five sigma bonds to the five oxygens. Then

put 6 LP electrons on each O. That totals 40 electrons. There are thus five sigma BPs around

the iodine, so the molecular and electronic geometries are both trigonal bipyramidal. The five

sigma BPs require five hybrid orbitals, so the hybridization must be sp

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Molecular Structure Information Sheet Page 3