Reaction Stoichiometry Chem 10 Review Worksheet Page 3
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1
2
3Answer Key
1. 2 Fe
O
(s) + 3 C (s) → 4 Fe (s) + 3 CO
(g)
2
3
2
a. 21.377 moles C
b. 0.493 moles Fe
O
2
3
c. 2.774 moles CO
2
2. 4 C
H
(ONO
)
(l) → 12 CO
(g) + 10 H
O (l) + 6 N
(g) + O
(g)
3
5
2
3
2
2
2
2
1.19 moles CO
, 0.995 moles H
O, 0.597 moles N
and 0.0995 moles O
would be formed.
2
2
2
2
3. 6 Mg (s) + P
(s) → 2 Mg
P
(s)
4
3
2
62.4 g P
4
4. 4 NH
(g) + 7 O
(g) → 4 NO
(g) + 6 H
O (g)
3
2
2
2
25
1.015 x 10
molecules H
O
2
5. CH
(g) + 4 Cl
(g) → CCl
(l) + 4 HCl (g)
4
2
4
31.4 lbs HCl
6. 2 Al (s) + 3 Br
(l) → 2 AlBr
(s)
2
3
Theoretical yield is 62.0 g, Percent yield is 96.8 %
7. 4 Fe (s) + 3 O
(g) → 2 Fe
O
(s)
2
2
3
a. LR is Fe
b. LR is Fe
c. LR is O
2
8. C
H
O
(s) + 8 KClO
(s) → 12 CO
(g) + 11 H
O (l) + 8 KCl (s)
12
22
11
3
2
2
LR is KClO
, 31.5 moles CO
, 28.9 moles H
O and 21.0 moles KCl will be produced
3
2
2
9. 2 BF
(g) + 3 H
(g) → 2 B (s) + 6 HF (g)
3
2
a. LR is BF
3
b. 35.39 g HF generated
c. 3.21 g of H
left over
2
d. Experimental yield is 25.69 g HF
10. 5 C (s) + 2 SO
(g) → CS
(l) + 4 CO (g)
2
2
LR is C, 74.6 g of CO are produced, and 9.73 g of SO
are left over.
2
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