Units Of Measurement And Applications Worksheet Page 16
ADVERTISEMENT
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44b
For a measurement given as 11.7 s, t he last signifi cant fi gure is in the ____ column.
Hence, the smallest scale on the measuring instrument is ____.
T he measurement has been made to the nearest ____.
Hence, the limit of reading = ____ .
1 _
GPE =
× ____ = ____
2
7
For each of the following measurements, fi nd :
i
the smallest unit of measurement (the limit of reading)
ii
the greatest possible error (GPE).
a
b
c
d
16 cm
286 g
38 m
16 L
e
f
g
h
3.6 kg
15.3 s
2.8 L
3.76 m
WORKED EXAMPLE 3
For each of the following measurements, fi nd:
i
ii
the smallest unit of measurement (the limit of reading)
the absolute error
iii
the lower and upper limits of the true measurement.
a
b
16 s
9.38 m
Solve
Think
Apply
a
i
The smallest unit of measurement is 1 s; that is,
Find the limit of
Find the limit of
this measurement of time has been made to the
reading (1 s) and
reading and the
nearest second.
the absolute error
greatest possible error.
Limit of reading = 1 s
(0.5 s) as in Worked
Lower limit
= measurement
Example 2.
1 _
Absolute error =
× 1 = 0.5 s
ii
− absolute error
2
Lower limit
Lower limit = 16 − 0.5 = 15.5 s
= 16 s − 0.5 s
iii
Upper limit
Upper limit = 16 + 0.5 = 16.5 s
= measurement
Upper limit
= 16 s + 0.5 s
+ absolute error
True measurement is between 15.5 and 16.5 s.
Smallest unit of measurement = 0.01 m; that is,
b i
Find the limit of
Note: The true
reading (0.01 m) and
this measurement of length has been made to the
measurement is
nearest 0.01 of a metre.
absolute error
greater than or equal
Limit of reading = 0.01 m
(0.005 m) as in
to the lower limit,
Worked Example 2.
but is less than the
1 _
Absolute error =
× 0.01 m = 0.005 m
ii
2
Lower limit
upper limit; that is,
Lower limit = 9.38 − 0.005 = 9.375 m
= 9.38 m − 0.005 m
iii
lower limit ⩽ true
Upper limit = 9.38 + 0.005 = 9.385 m
measurement < upper
Upper limit
= 9.38 m + 0.005 m
True measurement is between 9.375 and 9.385 m.
limit.
8
Complete the following f or a measurement of 2.6 kg .
Limit of reading = ____ kg
Absolute error = ____ kg
a
b
Lower limit of measurement = 2.6 − ____ kg . Upper limit of measurement = 2.6 + ____ kg
c
T he true measurement lies between ____ and ____.
9
For each of the measurements below, fi nd :
i
ii
the limit of reading
the absolute error in the measurement
iii
the lower and upper limits of the true measurement.
a
b
c
d
12 mm
348 g
375 mL
8.2 km
e
f
g
h
18.4 s
4.9 kg
2.37 m
5.81 L
50
Insight Mathematics General 11
ADVERTISEMENT
0 votes
Related Articles
Related forms
Related Categories
Parent category: Education