The Magic Chart Honors Physics Worksheet With Answers - Northern Highlands Page 5

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Problem Solving with Kinematics Equation 3
11. An object accelerates from rest with a constant acceleration of 7.5 m/s
. How fast will it be traveling after
2
Class Work
it goes 21 m?
v
= v
+ 2a x
v
=0 m/s
=√2(7.5 m/s
)(21 m)
=17.74 m/s
f 2
i 2
2
Given
Formula
Set up
Solution
a= 7.5 m/s
i
2
v
=?
x=21 m
f
12. An object experiences an acceleration of 9.8 m/s
over a distance of 210 m. After that acceleration it has a
2
velocity of 380 m/s. What was its initial velocity before being accelerated?
v
= v
+ 2a x
v
=?
(380 m/s)
=v
+ 2(9.8
=5.91 m/s
f 2
i 2
2
2
Given
Formula
Set up
Solution
a= 9.8 m/s
i
m/s
)(210 m)
i
2
2
v
=380 m/s
x=210 m
f
13. An object accelerates from rest to 24 m/s over a distance of 56 m. What acceleration did it experience?
v
= v
+ 2a x
v
=0 m/s
(24 m/s)
=2(a)(56 m)
=5.14 m/s
f 2
i 2
2
2
Given
Formula
Set up
Solution
a= ?
i
v
=24 m/s
x=56 m
f
14. A car which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s
over a distance of
2
340 m. How fast is it going after that acceleration?
v
= v
+ 2a x
v
=15 m/s
=√(15 m/s)
+ 2(6.5
=68.15 m/s
f 2
i 2
2
Given
Formula
Set up
Solution
a= 6.5 m/s
i
m/s
)(340 m)
2
2
v
=?
f
x=340 m
15. A car slams on its brakes creating an acceleration of -3.2 m/s
. It comes to rest after traveling a distance
2
of 210 m. What was its velocity before it began to accelerate?
v
= v
+ 2a x
v
=?
0 =v
+ 2(-3.2 m/s
)(210
=36.6 m/s
f 2
i 2
2
2
Given
Formula
Set up
Solution
i
i
a= -3.2 m/s
m)
2
v
=0 m/s
x=210 m
f
5 |
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