Aqueous Ions And Reactions Worksheet With Answers Page 9

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Other Schemes: Redox and Other (such as acid-base)
Reaction in Solution
Acid +
Base
Salt
+
Water
Conc. 0.15M
0.75M
H
SO
(aq) + 2NaOH (aq)  Na
SO
(aq) + 2H
O
2
4
2
4
2
Sulfuric Acid
Sodium Hydroxide
Sodium Sulfate Water
How many ml of NaOH to react completely with 50 ml of H
SO
?
2
4
?mL NaOH = (0.050L H
SO
)(0.15 mol H
SO
/ L)(2 mol NaOH/ 1 mol H2SO4)(1L/0.75 mol
2
4
2
4
NaOH) = 0.020 L = 20 ml
-3
= 0.0075 mol 50 ml 0.15M  7.5 x 10
H
SO
2
4
-3
NaOH = 0.0150 mol 25 ml 0.75M  1.5 x 10
Note: that this gives the needed 1:2 ratio
Need twice as much NaOH
-1
Summary: vol A –(conc)--> mol A –(Balanced Eq.)--> mol B –(conc
)--> vol B
Example:
How many grams BaSO
formed?
4
2+
2-
Ba
(aq) + SO
(aq)  BaSO
(s)
4
4
First you have to find how many moles formed?
20.0 ml of 0.150M Al
(SO
)
2
4
3
-3
-3
2-
(3(SO
)/ 1 Al
(SO
)
)(20 x 10
L)(0.150 mol Al
(SO
)
/ L) = 9.00 x 10
mol SO
4
2
4
3
2
4
3
4
30.0 ml of 0.200M BaCl
2
-3
-3
2+
(1 Ba/ 1 BaCl
)(30 x 10
L)(0.200 mol BaCl
/L) = 6.00 x 10
mol Ba
2
2
2+
2-
2-
2+
Ba
and SO
combine 1:1 so excess of SO
which mean Ba
limiting reactant
4
4
-3
6.00 x 10
mol BaSO
(233.4g BaSO
/ 1mol BaSO
) = 1.40g
4
4
4
List ions and possible combination (any insoluble? See rules)
Cations Anions
3+
2-
Al
and SO
is soluble
4
2+
-
Ba
and Cl
is soluble
3+
-
Al
and Cl
is soluble

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