graph when x <
and when x >
. Therefore, 1
> 2 sin x on 0 ≤ x < or
< x < 2π.
When the area is 36 square inches and the radius is
5-3 Solving Trigonometric Equations
5 inches, then the measure of θ is 3.01 radians.
Solve each inequality on the interval [0, 2 ).
51.
0 < 2 cos x –
50.
1 > 2 sin x
SOLUTION:
SOLUTION:
on [0, 2π). Use the zero
Graph y = 2 cos x –
Graph y = 1 and y = 2 sin x on [0, 2π). Use the
feature under the CALC menu to determine on
intersect feature under the CALC menu to
what interval(s) 0 < 2 cos x –
.
determine on what interval(s) 1 > 2 sin x.
The graphs intersect at about 0.524 or
and about
The zeros of y = 2 cos x –
are about 0.785 or
2.618 or
. The graph of y = 1 is above the other
and about 5.498 or
. The graph of y = 0 is
graph when x <
and when x >
. Therefore, 1
below the other graph when 0 ≤ x <
or
< x <
2π.
> 2 sin x on 0 ≤ x < or
< x < 2π.
Therefore, 0 < 2 cos x –
on 0 ≤ x <
or
<
x < 2π.
51.
0 < 2 cos x –
SOLUTION:
52.
≥
on [0, 2π). Use the zero
Graph y = 2 cos x –
feature under the CALC menu to determine on
SOLUTION:
what interval(s) 0 < 2 cos x –
.
Graph y =
and y =
on [0, 2π). Use
the intersect feature under the CALC menu to
determine on what interval(s)
≥
.
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