on the interval (–
, ), are found by adding integer
multiples of 2π. Therefore, the general form of the
(–
, ), are found by adding integer multiples of
2π. Therefore, the general form of the solutions is
solutions is
+ 2nπ,
+ 2nπ,
+ 2nπ,
+
5-3 Solving Trigonometric Equations
+ 2nπ,
+ 2nπ,
.
2nπ,
.
2
11.
9.
7 cot x –
= 4 cot x
6 tan
x – 2 = 4
SOLUTION:
SOLUTION:
The period of tangent is π, so you only need to find
The period of cotangent is π, so you only need to find
solutions on the interval
. The solutions on this
solutions on the interval
. The only solution on
interval are
and
. Solutions on the interval (–
this interval is
. Solutions on the interval (–
, ),
, ), are found by adding integer multiples of π.
are found by adding integer multiples of π.
Therefore, the general form of the solutions is
+
Therefore, the general form of the solutions is
+
nπ,
.
nπ,
+ nπ,
.
12.
7 cos x = 5 cos x +
2
10.
9 + sin
x = 10
SOLUTION:
SOLUTION:
The period of cosine is 2π, so you only need to find
The period of sine is 2π, so you only need to find
solutions on the interval
. The solutions on
solutions on the interval
. The solutions on
this interval are
and
. Solutions on the
and
this interval are
. Solutions on the interval
interval (–
, ), are found by adding integer
(–
, ), are found by adding integer multiples of
multiples of 2π. Therefore, the general form of the
2π. Therefore, the general form of the solutions is
solutions is
+ 2nπ,
+ 2nπ,
.
+ 2nπ,
+ 2nπ,
.
Find all solutions of each equation on [0, 2 ).
4
2
11.
7 cot x –
= 4 cot x
13.
sin
x + 2 sin
x − 3 = 0
SOLUTION:
SOLUTION:
The period of cotangent is π, so you only need to find
solutions on the interval
. The only solution on
this interval is
. Solutions on the interval (–
, ),
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Page 3
On the interval [0, 2π),
when x =
and
are found by adding integer multiples of π.