5-3 Solving Trigonometric Equations Worksheet With Answers Page 4

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interval (–
, ), are found by adding integer
The equation cos x = 2 has no real solutions since
multiples of 2π.  Therefore, the general form of the
the maximum value the cosine function can obtain is
1. On the interval [0, 2π), the equation
 has 
5-3 Solving Trigonometric Equations
solutions is
+ 2nπ,  
+ 2nπ,
.
solutions 0 and π.
2
Find all solutions of each equation on [0, 2 ).
15. 
4 cot x = cot x sin
x
4
2
13. 
sin
x + 2 sin
x − 3 = 0
SOLUTION:  
SOLUTION:  
The equations sin x = 2 and sin x = –2 have no real
solutions. On the interval [0, 2π), the equation cot x =
On the interval [0, 2π),
 when x =
 and 
0 has solutions
 and 
.
 when x =
. Since
 is not a real 
2
16. 
csc
x – csc x + 9 = 11
number, the equation
 yields no 
SOLUTION:  
additional solutions.
14. 
–2 sin x = –sin x cos x
SOLUTION:  
On the interval [0, 2π), the equation csc x = –1 has a
solution of
 and the equation csc x = 2 has
solutions of  
 and 
.
The equation cos x = 2 has no real solutions since
the maximum value the cosine function can obtain is
3
2
17. 
cos
x + cos
x – cos x = 1
1. On the interval [0, 2π), the equation
 has 
solutions 0 and π.
SOLUTION:  
2
15. 
4 cot x = cot x sin
x
SOLUTION:  
On the interval [0, 2π), the equation cos x = 1 has a
solution of 0 and the equation cos x = –1 has a
The equations sin x = 2 and sin x = –2 have no real
solution of  π.
solutions. On the interval [0, 2π), the equation cot x =
 and 
2
0 has solutions
.
18. 
2 sin
x = sin x + 1
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Page 4
SOLUTION:  
2
16. 
csc
x – csc x + 9 = 11

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