Chemical Bonding And Molecular Structure Worksheet With Answer Key Page 2

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Chemical Bonding and molecular structure
Ans: 3
2
CO
2
Sol: In
carbon under goes sp
hybridization and shape of the ion is trigonal planar. While shape
3
+
2
BF , NH and SO
of
have tetrahedral structure.
4
4
4
I
5.
is linear
3
Assertion (A) :
[ 2007 M ]
Reason (R) : It is not in sp hybridised state.
The correct answer is
1. Both A and R are true and R is the correct explanation of A
2. Both A and R are true but R is not the correct explanation of A
3. A is true, R is not true
4. A is not true but R is true
Ans :2
I
3
Sol:
is linear . There is sp
d hybridsation but not sp. But R is not correct explanation of A.
3
2
6.
A molecule (X) has i) four sigma bonds formed by the overlap of sp
and s orbital. (ii) One sigma
2
2
orbitals and iii) one π bonds is formed by P
bond formed by sp
and sp
and P
orbitals. Which
x
x
of the following is X ?
[ 2006 E]
C H
C H Cl
C H Cl
C H
1)
2)
3)
4)
2
6
2
3
2
2
2
2
4
H
H
=
C C
H
H
Sol:
(
)
(
)
σ
=
σ
=
2
2
2
sp
sp
1
sp
s
4
; π = 1
;
1
7.
H – O – H bond angle is H
O is 104.5° and not 109°28
because of
[ 2006 M ]
2
1) lone pair – lone pair repulsion
2) lone pair –bond pair repulsion
3) bond pair – bond pair repulsion
4) high electronegativity of oxygen
Ans: 1
H O oxygen atom undergoes sp
3
Sol: In
hybridization and shape of the molecule must be tetrahedral
2
1
and bond angle must be 109°28
. But due to the repulsion between lone pair and lone pair of
electron shape of the molecule is distorted to angular (or) ‘V’ shape and bond angle is decreases
to 104°.5°
8.
Which of the following molecule has zero dipolemosanthoshiment?
(2005-M)
NH
BeCl
H O
2) HCl
1)
3)
4)
3
2
2
Ans: 1
BeCl has symmetrical and linear structure hence (i) is correct
Sol.
2
9.
Which of the following is a favourable factor for cation formation?
(2005-M)
1. Low ionisation potential
2. High electron affinity
3. High electronegativity
4. Small atomic size
Ans : 1
Sol. Low IP favours cation ion formation
10.
Which of the following is a linear molecule?
(2005-E)
BeCl
H O
SO
CH
1)
2)
3)
4)
2
2
2
4
Ans: 1
BeCl = Linear
Sol.
H
O = Angular
2
2
SO
= Angular
CH
= tetrahedral
2
4
2

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