General Chemistry Ii Jasperse - Electrochemistry Extra Practice Problems With Answers Page 11
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K Values and Voltage Key Equation: log K = nE˚/0.0592
56. When a voltaic cell reaches equilibrium, __________
a.
E= 0
d.
E= K
T
b.
E
= 0
e.
E
= Q
cell
cell
c.
E
= K
cell
57. Electrochemical cell potentials can be used to determine equilibrium constants that would be otherwise difficult to
determine because concentrations are small. What is Κ for the following balanced reaction, if E˚ = +0.0218 V?
Answer Key
Error
3+
+2
3Zn(s) + 2Cr
(aq) → 3Zn
(aq) + Cr(s)
E˚ = +0.0218 V
-3
a. 1.3 x 10
-4
b. 2.3 x 10
c. 2.2
d. 0.37
10
58. What is E˚ for the following balanced reaction, if K=4.38 x 10
?
2+
+2
10
Zn(s) + Fe
(aq) → Zn
(aq) + Fe(s)
K= 4.38 x 10
a. -0.578 V
b. +0.866 V
c. -0.315 V
d. +0.315 V
T
Nonstandard Concentrations and Cell Potential. Key Equation: E cell = E˚ – [0.0592/n]log Q
2+
59. The value of E˚ for the following reaction is 1.10 V. What is the value of E
when the concentration of Cu
is 1.0 M
cell
2+
and the concentration of Zn
is 0.025 M?
2+
2+
(aq) ! Cu (s) + Zn
Zn(s) + Cu
(aq)
E˚ = 1.10 V
1.0 M
0.025 M
a. 1.40 V
b. 0.95 V
c. 1.15 V
d. 0.80 V
60. The value of E˚ for the following reaction is 1.260 V. What is the value of E
given the concentrations shown?
cell
2+
3+
(aq) ! 3Cd (s) + 2Al
2Al(s) + 3Cd
(aq)
E˚ = 1.260 V
0.1 M
0.6 M
a. 1.235 V
b. 1.285 V
c. 1.15 V
d. 1.37 V
T
61. The value of E˚ for the following reaction is 0.189 V. What is the value of E
given the concentrations shown?
cell
+
-
3+
4H
(aq) + Fe(s) + NO
(aq) → Fe
(aq) + NO(aq) + 2H
O(l)
E˚ = 0.189 V
3
2
0.1 M
0.6 M
1.0 M
0.5 M
a. -0.215 V
b. 0.112 V
c. 0.189 V
d. 0.266 V
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