Chemistry 102, Test Chapter 13-14 Worksheet With Answers - 1997 Page 7
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11Answer: 1. 93
Note: See Problem 22, Chapter 12
(g) ↔ 2NH
N
(g) + 3H
(g)
2
2
3
Equilibrium concentrations:
[NH
] = 0.50 M
3
2
[NH
]
3
Kc =
[N
] = 0.10 M
[H
] = 0.30 M
2
2
3
[N
][H
]
2
2
2
[0.50]
Kc =
Kc = 93
3
[0.10][0.30]
17.(19)A mixture of 0.50 M CO and 0.40 M Br
were placed in a container and allowed to come to
2
equilibrium. At equilibrium the concentration of COBr
was 0.233 M. What is the value
2
of Kc for the reaction?
CO(g) + Br
(g)
COBr
2
2
1. 5.23
2. 1.17
3. 0.858
4. 0.191
Answer: 1. 5.23
↔
CO
+
Br
COBr
2
2
Initial
0.50 M
0.40 M
0
Change
-0.233 M -0.233 M
+0.233 M
Note: 1:1:1 mole ratio
Equi:
0.267 M
0.167 M
0.233 M
[COBr
0.233
2
Kc =
=
= 5.23
[CO][Br
]
[0.267][0.167]
2
18.(20 Consider the equilibrium SO
(g) + Cl
(g)
SO
Cl
(g) for which Kp = 91. A
2
2
2
2
gaseous reaction mixture contains 0.35 atm of SO
, 0.24 atm of Cl
and 0.19 atm of
2
2
SO
Cl
. Which of the following statements is true?
2
2
1. The mixture is at equilibrium.
2. The reaction will move from left to right to reach equilibrium.
3. The reaction will move from right to left to reach equilibrium.
Answer: 2
Note: This is Problem 26, chapter 12
Calculate Q - Reaction Quotient:
P
0.19
SO2 Cl2
Q =
=
= 2.26
Initial pressures are used in calculating Q
P
x P
(0.35)(0.24)
SO 2
Cl2
Q < K
2.26 < 91 Q is too small; the ratio of products to reactants is too small.
Reactions proceeds from left to right (→) to increase product and decrease reactant, raising
the value of the product: reactant ratio.
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