Chemistry 102, Test Chapter 13-14 Worksheet With Answers - 1997 Page 9
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114. Add a catalyst: this speeds up the rate at which equilibrium is reached, but will not
cause a shift in the equilibrium.
21.(25 Consider this reaction system
-
∆H =
2 NO(g) + O
(g)
2 NO
(g)
114 kJ
2
2
The conditions which would favor maximum conversion of the reactants to products would
be
1. high temperature and high pressure.
2. high temperature and low pressure.
3. low temperature and high pressure.
4. low temperature and low pressure.
Answer: 3. Low temperature, high pressure
The reaction must shift to the right for maximum conversion of reactants to products:
Temperature : the reaction produces heat as it proceeds from left to right and consumes heat
as it proceeds right to left ( the reaction is exothermic; ∆H is negative).Running the reaction
under conditions of LOW temperature would cause the reaction to shift to the right so as to
produce more heat in an attempt to raise the temperature.
External change - lower temperature
Equilibrium response - produce more heat to raise temperature.
Pressure : Under conditions of HIGH pressure , the reaction would shift right to produce
fewer moles of gas in an attempt to reduce the pressure.
↔
2NO(g) + O
(g)
2NO
(g)
2
2
2 + 1 = 3 gas moles
2 gas moles
higher pressure
lower pressure
External change: high pressure
Equilibrium response: produce fewer moles of gas to lower or reduce pressure.
22.(15)Which of the following statements concerning equilibrium is not true?
1. The equilibrium constant is independent of temperature.
2. A system that is disturbed from an equilibrium condition responds in a manner to
restore equilibrium.
3. At equilibrium, two opposing processes balance each other.
4. The value of the equilibrium constant for a given reaction is the same regardless of the
direction from which equilibrium was attained.
Answer: 1.
K, equilibrium constant, is dependent on temperature.
the equation you used in Summary Problem, Part (g) gives this temperature - K relationship:
∆H
o
K
1
1
〈
〉
2
ln
=
-
K
R
T
T
1
1
2
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