U N I T - 8
−
× −
3
7
( 2)
( 2)
Example 8 : Simplify
×
6
3 4
+
−
× −
−
3
7
3 7
( 2)
( 2)
( 2)
=
Solution
:
{a
m
× a
n
= a
m+n
}
( )
×
6
6
3 4
×
2
3
2
−
10
( 2)
m
n
m×n
=
{(a
)
= a
}
×
12
3 2
−
−
10
10 12
( 2)
2
÷ a
m
n
m–n
10
10
=
=
{a
= a
, (–2)
= 2
}
×
12
3
3 2
–2
2
1
1
=
=
=
×
2
3
3 2
12
Example 9 : Find x so that (–5)
x+1
× (–5)
5
= (–5)
7
x+1
5
7
Solution
: (–5)
× (–5)
= (–5)
x+1+5
7
m
n
m+n
(–5)
= (–5)
{a
× a
= a
}
x+6
7
(–5)
= (–5)
On both sides, powers have the same base, so their
exponents must be equal.
Therefore,
x + 6 = 7
x = 7 – 6 = 1
x = 1
Application
Application
Application
Application
Application
on
on
on
on
on
Problem
Problem
Problem
Problem
Problem
Solving
Solving
Solving
Solving
Solving
Strategy
Strategy
Strategy
Strategy
Strategy
Example 10 :
Find x so that (–5)
x+1
× (–5)
5
= (–5)
7
Understand and Explore the Problem
•
What are you trying to find?
The value of x which satisfies the given equation.
Plan a Strategy
•
You know the laws of exponents. Applying the laws of exponent
in the given equation to find the value of x.
E E E E E
P P P P P
247
247
247
247
247
XPONENTS
XPONENTS
AND
AND
OWERS
OWERS
XPONENTS
XPONENTS AND
XPONENTS
AND
AND
OWERS
OWERS
OWERS