Worksheet 14 - Hybridization With Answers (Page 2 of 5) in pdf

Worksheet 14 - Hybridization With Answers Page 2

In some Lewis structures, there are only three equivalent bonds formed. To create

three equivalent hybridized orbitals, mix three atomic orbitals.

Draw and name the orbitals formed in this hybridization, then add the electrons for

sulfur. Since the hybridized orbitals are close in energy, every orbital is filled with one

electron before electrons are paired.

energy

hybridization

___ σ bond(s).

The hybridized orbitals will form __

___ π bond(s).

The unhybridized orbital will form __

There will be __

___ lone pair(s).

This hybridization gives trigonal planar geometry.

In linear molecules, like CO

, the central atom has only two equivalent bonding orbitals.

Draw the energy levels and name the orbitals formed in this hybridization.

energy

hybridization

Fill in the electrons for carbon and determine the number and type of bonds formed.

There will be 2 sigma bonds (with sp) and 2 pi bonds (with p)

In CO

, determine the hybridization of the oxygen atoms. Complete the energy

diagram for the oxygens. Draw the structure of CO

energy

O C O

C O

hybridization

Each oxygen atom forms 1 sigma bond (with the sp

) and 1 pi bond

(with the p) with the sp and p orbitals on the carbon atom

Worksheet 14 - Hybridization With Answers Page 2