Chem 3411 Solution Set 5 - Mindanao State University - Iligan Institute Of Technology - 2010 Page 14

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CHEM 3411, Fall 2010
Solution Set 5
n
l
liquid
liquid
n
=
N
H
(solid)
2
4
l
N
H
(solid)
2
4
n
liquid
χ
=
liquid
n
+ n
liquid
N
H
(solid)
2
4
n
liquid
=
n
l
liquid
liquid
n
+
liquid
l
N 2 H 4 (solid)
1.000
=
l
liquid
1.000 +
l
N 2 H 4 (solid)
1.000
=
0.26
1.000 +
0.40
= 0.6061
Therefore we’ve found that 61% of the sample will be in the mixed liquid phase with the remaining 39% in the
percipitated solid N
H
phase.
2
4
0
Liquid
2 0
¡
=0
34
¢
.
N
H
2
2
4 0
¡
Liquid +
6 0
N
H
2
2
¡
Eutectic
Liquid +
Melt
NH
3
8 0
¡
Solid
0.0
0.2
0.4
0.6
0.8
1.0
Mole Fraction of
,
N
H
2
2
N
H
2
2
Figure 1: Phase diagram of NH
/N
H
system
3
2
4
14

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