Solution Stoichiometry Worksheet Page 4

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-2
-3
Initial
1.06 x 10
mol
5.31 x 10
mol
0
0
-2
-3
-3
-2
Change
-1.06 x 10
mol
-5.31 x 10
mol
+5.31 x 10
mol +1.06 x 10
mol
Final
0
0
0
0
1 L
⎛
⎞
-2
-2
1.06 x 10
mol KOH
⎜
0.406 mol KOH = 2.62 x 10
⎟
L or 26.2 mL
⎝
⎠
CHEM 1314
4
FALL 2005

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