Redox And Electrochemistry Worksheet With Answer Key Page 5
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8REDOX & ELECTROCHEMISTRY ANSWERS
#1 Answer:
sec
(a) (1.100 hr)(3600
) = 3960 sec.
hr
(3960 sec)(0.125 amp) = 495 coul
1 farad
495 coul ×
-3
= 5.13
×
10
faraday
96500 coul
3+
2+
→
(b) Fe
+ 1e-
Fe
-
+
2+
→
(c) MnO
+ 8 H
+ 5e-
Mn
+ 4 H
O
4
2
2+ →
3+
5 Fe
5 Fe
+ 5e-
________________________________________________
-
+
2+ →
3+
2+
MnO
+ 8 H
+ 5 Fe
5 Fe
+ Mn
+ 4 H
O
4
2
2+
-
1
1 mol Fe
1 mol MnO
−3
−
4
farad ×
×
×
= 0.0416M MnO
(d) 5.13×10
4
2+
1 farad
0.02465L
5 mol Fe
#2 Answer:
+
+
–
(a) Na
is not reduced as easily as H
O (or H
or OH
). OR
2
+
If Na
were formed, it would rapidly react with water to reform Na
.
(s)
+
→
(b) Anode: 2 H
O
O
+ 4 H
+ 4e-
2
2
-
→
cathode: 2 H
O + 2e-
H
+ 2 OH
2
2
+
→
or: 2 H
+ 2e-
H
2
- →
(c) anode: 2 Cl
Cl
+ 2e-
2
-
→
cathode: 2 H
O + 2e-
H
+ 2 OH
2
2
+
→
or: 2 H
+ 2e-
H
2
(d) H
- “pop” with a lit splint; O
- ignites a glowing splint; Cl
- yellowish-green color
2
2
2
(other suitable tests accepted)
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