Redox And Electrochemistry Worksheet With Answer Key Page 8
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8#6 Answer:
−
1 mol e
60sec.
35.0min
(a) 2.50amp ×
×
×
×
96500amp ⋅ sec
1min.
1
1 mol M
− 2
×
= 2.72×10
mol
−
2 mol e
mol = 112 g/mol; ∴ metal is Cd
-2
3.06 g / 2.72
10
×
2+
→
(b) Zn
Zn
+ 2e-
E ˚ = +0.76 v
2+
→
Cd
+ 2e-
Cd
E ˚ = -0.40 v
_______________________________________
2+
2+
→
Cd
+ Zn
Cd + Zn
E ˚ = +0.36 v
(c)
G ˚ = - nFE ˚ = -(2)(96.5 kJ/v)(0.36v) = -69 kJ
2+
0.0592
[Zn
]
= EÞ −
(d) E
log
cell
2+
n
[Cd
]
0.0592
0.10
= 0.36v −
= 0.39v
E
log
cell
2
1
#7 Answer:
2+ →
3+
(a) 2 Cr + 3 Cu
2 Cr
+ 3 Cu
2+
Cr = reducing agent; Cu
= oxidizing agent
(b) (i) Cu is cathode
(ii) salt bridge
(iii) transfer of ions or charge but not electrons
(c) E
decreases.
cell
use the Nernst equation to explain answer
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