Radioactive Decay And Acid Dissociation Constant Chap. 9 And 10 Worksheet With Answers - Middle Tennessee State University Page 4
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20Solution
+
-5
+
-14
+
-8
a) [H
] = 3.55 x 10
M b) [H
] = 7.586 x 10
M
c) [H
] = 1.86 x 10
M
+
-
9.41 Convert the following pH values into both [H
] and [OH
] values:
a) pH = 8.00
b) pH = 6.15
c) pH = 1.30
Solution
- 14
1.00 x10
+
- 8
-
- 6
[H
]= 1.00 x10
M [OH
]=
=1.00 x10
M
a)
- 8
1.00 x10
- 14
1.00 x10
+
- 7
-
- 8
[H
]= 7.08 x10
M
[OH
] =
= 1.41x10
M
b)
- 7
7.08 x10
- 14
1.00 x10
+
- 2
-
- 13
[H
]= 5.01x10
M [OH
]=
= 2.00 x10
M
- 2
c)
5.01x10
9.45 The pH values of specific samples of food items are listed below. Convert each
+
value to [H
] and classify the sample as acidic, basic, or neutral.
a) milk, pH = 6.39
b) coffee, pH = 5.10
c) orange juice, pH = 4.07
d) vinegar, pH = 2.65
Solution
+
-7
+
-6
a) [H
] = 4.07 x10
M; acidic
b) [H
] = 7.94 x10
M; acidic
+
-5
+
-3
c) [H
] = 8.51 x10
M; acidic
d) [H
] = 2.24 x10
M; acidic
Properties of Acids (Section 9.6)
9.47 Use the information in Table 9.4 and describe how you would prepare each of
the following solutions.
a) about 750 mL of 0.500 M H
SO
from dilute sulfuric acid
2
4
b) about 200 mL of 0.1 M NaOH from stock sodium hydroxide solution
c) about 1.0 L of 1.0 M acetic acid from glacial acetic acid
Solution
V
x C
d
d
V
=
c
Solve equation 7.9 for V
.
C
c
c
2
a)
or 1 x 10
using question values
750 mlx 0.500 M
V
=
= 125 mL
Measure 125 mL of the dilute (3 M) H
SO
and
c
3.00 M
2
4
put it in
enough water (about 625 mL) to make 750 mL solution.
b)
Take 3 mL of stock NaOH and put it in enough
200 ml x 0.1M
V
=
= 3 mL
c
water (about 197 mL) to make 200 mL solution.
6 M
c)
1.0 L x 1.0 M
or 6 rounded for question value
1000 mL = 56 mL
V
x
=
c
18 M
1L
Measure 56 mL glacial acetic acid and
put it in enough water (about 944 mL) to make 1.0 L solution.
9.53 Write balanced molecular equations to illustrate five different reactions that
could be used to prepare BaCl
from hydrochloric acid (HCl) and other
2
appropriate substances:
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