Radioactive Decay And Acid Dissociation Constant Chap. 9 And 10 Worksheet With Answers - Middle Tennessee State University Page 5

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Solution
a) BaO(s) + 2HCl(aq)  BaCl
(aq) + H
O(l)
2
2
(s) + 2HCl(aq)  BaCl
b) Ba(OH)
(aq) + 2H
O(l)
2
2
2
(s) + 2HCl(aq)  BaCl
c) BaCO
(aq) + 2H
O(l) + CO
(g)
3
2
2
2
(s) + 2HCl(aq)  BaCl
d) Ba(HCO
)
(aq) + 2H
O(l) + 2CO
(g)
3
2
2
2
2
e) Ba(s) + 2HCl(aq)  BaCl
(aq) + H
(g)
2
2
Salts (Section 9.8)
9.61 Identify with ionic formulas the cations and anions of the following salts:
a) LiCI
b) Cu(NO
)
c) SrSO
3
2
4
d) K
PO
e) K
HPO
f) CaCO
3
4
2
4
3
Solution
-
+
-
2+
+
2 -
a) Li
, Cl
b) Cu
, 2NO
c) Sr2
, SO
3
4
+
+
2+
2 -
3 -
2 -
d) 3K
, PO
e) 2K
, HPO
f) Ca
,
CO
4
4
3
9.65 Calculate the mass of water that would be released if the water of hydration
were completely driven off 1.0 mol of: (a) plaster of Paris and (b) gypsum (see
Table 9.6). How would the products of these reactions compare?
Solution
From Table 9.6, plaster of Paris is CaSO
•H
O and gypsum is CaSO
•2H
O.
4
2
4
2
1mol H
O
18 g H
O
2
2
1mol CaSO
: H
O x
x
= 18 g H
O
4
2
2
1mol CaSO
: H
O
1molH
O
a)
4
2
2
2 mol H
O
18 g H
O
2
2
1mol CaSO
: H
O x
x
= 36 g H
O
4
2
2
1mol CaSO
: H
O
1molH
O
b)
4
2
2
The products are water (H
O) and CaSO
in both cases. The amount of
2
4
water is greater from gypsum.
9.67 Write formulas for the acid and indicated a solid that could be used to prepare
each of the following salts: a) CuCl
(solid is an oxide); b) MgSO
(solid is a
2
4
carbonate); c) LiBr (solid is a hydroxide)
Solution
a) HCI and CuO
b) H
SO
and MgCO
c) HBr and LiOH
2
4
3
9.69 Write balanced full equations to illustrate each salt preparation described in
Exercise 9.67.
Solution
a) CuO + 2HCl  CuCl
+ H
O
2
2
 MgSO
b) MgCO
+ H
SO
+ H
O + CO
3
2
4
4
2
2
c) LiOH + HBr  LiBr + H
O
2
9.73 Determine the number of equivalents and milliequivalents in each of the
-2
following:
a) 0.10 mol KI
b) 0.25 mol MgCl
c) 4.73 x 10
mol AgNO
2
3

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